3log(x^y) - 2log(xy^5) anyone feel like simplifying this for me? Seriously when it comes to highschool revision I (and most of the class with me it would seem) fail miserably.... I worked out the answer but I am too embarassed to share it with you until I get a second opition.
log((x^(3y))/(x^2y^10)) or log((x^(3y))/((xy^5)^2)) ...wait. do you want as few logs as possible or as many logs as possible? 3ylog(x) - 2log(x) - 10log(y)